Algebra · StudentHub Lesson

Quadratic Equations

Solve quadratic equations by factoring, using the difference of squares and the zero product rule.

25 minIntermediate
01

What you will learn

  • Recognize the standard form of a quadratic equation
  • Factor simple quadratics and difference of squares
  • Apply the zero product property
  • Solve for two possible roots
  • Verify solutions by substitution
02

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How To Solve Quadratic Equations By Factoring - Quick & Simple! · The Organic Chemistry Tutor

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03

Topic notes

Main Idea

A quadratic equation has the form ax^2 + bx + c = 0. Many can be solved by factoring into two binomials and using the zero product rule.

Key Concepts

  • Difference of squares: a^2 - b^2 = (a+b)(a-b)
  • Factoring trinomials: find two numbers that multiply to c and add to b
  • Zero product rule: if two factors multiply to zero, at least one must be zero

Definitions

  • Quadratic equation: an equation with a squared variable term
  • Root/Solution: value(s) of x that satisfy the equation
  • Factoring: rewriting an expression as a product of simpler expressions

Formulas

  • Standard form: ax^2 + bx + c = 0
  • Difference of squares: x^2 - k^2 = (x-k)(x+k)

Examples

  • x^2 - 49 = 0 → (x-7)(x+7) = 0 → x = 7 or x = -7
  • x^2 + 5x + 6 = 0 → (x+2)(x+3) = 0 → x = -2 or x = -3

Common Mistakes

  • Forgetting a quadratic can have two solutions
  • Sign errors when factoring
  • Applying the zero product rule before setting the equation equal to zero
04

Key concepts

Standard form ax²+bx+c=0Difference of squaresFactoring trinomialsZero product ruleTwo roots
05

Important terms

Quadratic
A polynomial equation with highest power 2.
Factoring
Writing an expression as a product of factors.
Root
A solution to the equation.
06

Worked examples

Problem

Solve x^2 - 49 = 0

  1. 1. Recognize difference of squares
  2. 2. Factor: (x-7)(x+7) = 0
  3. 3. Set each factor to zero
  4. 4. x = 7 or x = -7

Answer: x = 7 or x = -7

Problem

Solve x^2 + 5x + 6 = 0

  1. 1. Find two numbers multiplying to 6 and adding to 5: 2 and 3
  2. 2. Factor: (x+2)(x+3) = 0
  3. 3. Set each factor to zero
  4. 4. x = -2 or x = -3

Answer: x = -2 or x = -3

07

Quick revision

  • Set the equation equal to zero first
  • Look for the difference of squares pattern
  • Find factor pairs for trinomials
  • Zero product rule gives two solutions
  • Always check both roots
  • Not all quadratics factor nicely
08

Check your understanding

Question 1 · Multiple choice

Factor x² - 9

Question 2 · Multiple choice

Solve x² - 4 = 0

Question 3 · Short answer

Solve x² + 7x + 12 = 0

Question 4 · Short answer

Solve x² - x - 6 = 0

Question 5 · True or false

A quadratic equation can have two different solutions.

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